KCL at the supernode yields:
(V2 - V1) / R1
+ ( V2 - 0) / R2
+ (V3 - 0) / R4
=0
(-1) V1
+ (5/4) V2
+ (1/8) V3 = 0
The SAME result we had above when we combined the
two equations to eliminate i2.
KCL at V1 yields:
is =
(1/R1 + 1/R2 + 1/R\pi + 1/RF) V1
+ (-1/RF) V1
KCL at V2 yields:
(gm - 1/RF) V1
+ (1/RF + 1/RL ) V2
= 0
Same as previous example except second node voltage is known:
V2 = g V1
Need supernode as shown above
KCL at the supernode yields:
(V2 - V1) / R1
+ ( V2 - 0) / R2
+ (V3 - 0) / R4
=0
(-1) V1
+ (5/4) V2
+ (1/8) V3 = 0
KCL at the V1 yields:
is = (V1 - V2)
/ R1
And our final equation (from the supernode) is:
V2 = V3 + g V1
PROCEDURE: